Question:

What is the value of $i^{99}$ (where $i$ is the imaginary unit)?

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Powers of $i$ repeat in a cycle of 4: $i, -1, -i, 1$.
Updated On: Jan 20, 2026
  • 1
  • $-1$
  • $i$
  • $-i$
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The Correct Option is D

Solution and Explanation

Step 1: Recall powers of $i$.
\[ i^1 = i,\quad i^2 = -1,\quad i^3 = -i,\quad i^4 = 1 \]
Step 2: Use cyclic nature.
Powers of $i$ repeat every 4 terms.
Step 3: Reduce the exponent.
\[ 99 \div 4 = 24 \text{ remainder } 3 \]
Step 4: Find the value.
\[ i^{99} = i^3 = -i \]
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