Question:

What is the oxidation number of sulfur in sulfuric acid (H$_2$SO$_4$)?

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When determining the oxidation state of an element in a compound, balance the total oxidation states based on known values for other elements in the compound.
Updated On: Apr 15, 2025
  • 4
  • 6
  • 8
  • None of the above
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The Correct Option is B

Solution and Explanation

Step 1: Understand the chemical formula.
Sulfuric acid is represented as H2SO4.

Step 2: Know the oxidation numbers of known elements:
- Hydrogen (H) has an oxidation number of +1.
- Oxygen (O) has an oxidation number of -2.

Step 3: Let the oxidation number of sulfur (S) be x.
Total oxidation number of the molecule is 0 (since H2SO4 is a neutral compound).

Step 4: Write the oxidation number equation:
(2 × +1) + (1 × x) + (4 × -2) = 0
⇒ 2 + x - 8 = 0
⇒ x = 6

Final Answer: +6

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