Step 1: Nitration of Benzoic Acid
The first step is the nitration of benzoic acid using concentrated \( \text{HNO}_3 \) and concentrated \( \text{H}_2\text{SO}_4 \). This is an electrophilic aromatic substitution reaction. The carboxylic acid group ( -COOH) is a deactivating and meta-directing group. Therefore, the major product expected from the nitration of benzoic acid under normal conditions is m-nitrobenzoic acid.
However, the provided solution for this question (indicated by the marked correct option in the image) implies that X is ortho-nitrobenzoic acid. For the purpose of solving this specific problem, we proceed with the assumption that X is ortho-nitrobenzoic acid.
Step 2: Reduction of X (ortho-nitrobenzoic acid) with \( \text{B}_2\text{H}_6 \)
The second step involves the reaction of X (ortho-nitrobenzoic acid) with (i) \( \text{B}_2\text{H}_6 \) (diborane) followed by (ii) \( \text{H}_3\text{O}^+ \) (acidic workup).
Diborane ( \( \text{B}_2\text{H}_6 \) ) is a highly selective reducing agent. It effectively reduces carboxylic acids (R-COOH) to primary alcohols (R-\( \text{CH}_2\text{OH} \)). A crucial aspect of diborane's selectivity is that it does not reduce nitro groups ( \( \text{-NO}_2 \) ). In contrast, other strong reducing agents like \( \text{LiAlH}_4 \) would reduce both carboxylic acids and nitro groups.
Therefore, when ortho-nitrobenzoic acid (X) reacts with diborane, only the carboxylic acid group will be reduced to an alcohol, while the nitro group will remain intact. This leads to the formation of ortho-nitrobenzyl alcohol as product Y.
Conclusion:
Based on the assumed structure of X (ortho-nitrobenzoic acid from the given correct option) and the known selectivity of diborane as a reducing agent, X is ortho-nitrobenzoic acid and Y is ortho-nitrobenzyl alcohol. This matches option (1).