Question:

Using prime factorisation, find the HCF of 180, 140 and 210.

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List the prime factors of each number and take the product of the lowest powers of common factors.
Updated On: May 20, 2025
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Solution and Explanation

Prime factorisations: \[ 180 = 2^2 \times 3^2 \times 5
140 = 2^2 \times 5 \times 7
210 = 2 \times 3 \times 5 \times 7 \] Common prime factors in all three numbers = \(2^1 \times 5 = 10\)
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