Given:
Find HCF of 144, 180, and 192 using prime factorisation.
Step 1: Prime factorisation of each number
\[
144 = 2^4 \times 3^2
\]
\[
180 = 2^2 \times 3^2 \times 5
\]
\[
192 = 2^6 \times 3
\]
Step 2: Identify common prime factors with smallest powers
- For prime factor 2: smallest power among 4, 2, 6 is \(2\).
- For prime factor 3: smallest power among 2, 2, 1 is \(1\).
- Prime factor 5 is not common to all.
Step 3: Calculate HCF
\[
\text{HCF} = 2^2 \times 3^1 = 4 \times 3 = 12
\]
Final Answer:
\[
\boxed{12}
\]