For Fe3+ (d5 configuration), the number of unpaired electrons depends on the ligand field strength.
(I) With a strong field ligand, the d-orbitals split, causing pairing of electrons. Thus, Fe3+ in the presence of a strong field ligand will have 0 unpaired electrons.
(II) With a weak field ligand, the d-orbitals do not split enough to cause electron pairing. Therefore, Fe3+ in the presence of a weak field ligand will have 5 unpaired electrons.
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below