Two vertical parallel mirrors A and B are separated by 10 cm. A point object O is placed at a distance of 2 cm from mirror A. The distance of the second nearest image behind mirror A from the mirror A is ___cm
Show Hint
For multiple reflections, calculate distances iteratively for each reflection
Correct Answer: 18
Solution and Explanation
Step 1: Calculate the positions of images formed by multiple reflections - The distance of the first image from mirror A is \[ 2 \, \text{cm}. \] The distance of the first image from mirror B is \[ 10 + 2 = 12 \, \text{cm}. \] The distance of the second image from mirror A is \[ 10 + 12 = 22 \, \text{cm}. \] The distance of the second nearest image behind mirror A is \[ 18 \, \text{cm}. \]
Final Answer: The distance of the second nearest image is 18 cm.
Top Questions on Spherical Mirrors
- A concave mirror produces an image of an object such that the distance between the object and image is 20 cm. If the magnification of the image is \( -3 \), then the magnitude of the radius of curvature of the mirror is:
- JEE Main - 2025
- Physics
- Spherical Mirrors
- (ii) An object at a distance of 16 cm from a spherical mirror forms a virtual image at a distance of 12 cm behind the mirror. Determine the magnification of the image and type of the mirror.
- UP Board X - 2025
- Science
- Spherical Mirrors
- Image of an object formed by a concave mirror is real and of the size of the object. The object is placed -
- UP Board X - 2025
- Science
- Spherical Mirrors
- With the help of a suitable ray diagram, derive the formula \( \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \) for a concave mirror.
- UP Board XII - 2025
- Physics
- Spherical Mirrors
- The length of the image formed by a concave mirror:
- UP Board XII - 2025
- Physics
- Spherical Mirrors
Questions Asked in JEE Main exam
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is:
- JEE Main - 2026
- Thermodynamics
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
- JEE Main - 2026
- Coordinate Geometry
- A voltage regulating circuit consisting of a Zener diode having breakdown voltage of $10\,\text{V}$ and maximum power dissipation of $0.4\,\text{W}$ is operated at $15\,\text{V}$. The approximate value of protective resistance in this circuit is ___ $\Omega$.
- JEE Main - 2026
- Semiconductor electronics: materials, devices and simple circuits
- Two point charges of \(1\,\text{nC}\) and \(2\,\text{nC}\) are placed at two corners of an equilateral triangle of side \(3\) cm. The work done in bringing a charge of \(3\,\text{nC}\) from infinity to the third corner of the triangle is ________ \(\mu\text{J}\). \[ \left(\frac{1}{4\pi\varepsilon_0}=9\times10^9\,\text{N m}^2\text{C}^{-2}\right) \]
- JEE Main - 2026
- Electrostatics
Consider the following two reactions A and B:
The numerical value of [molar mass of $x$ + molar mass of $y$] is ___.
- JEE Main - 2026
- Organic Chemistry