The total number of outcomes when two dice are rolled is \( 6 \times 6 = 36 \), as each die has 6 faces.
To find the favorable outcomes where the sum is 3, we look for all pairs of dice rolls that sum to 3: \[ (1,2), (2,1) \] Thus, there are 2 favorable outcomes. The probability is the ratio of favorable outcomes to total outcomes: \[ P(sum = 3) = \frac{2}{36} = \frac{1}{18} \] To find the probability of a specific sum in dice rolling, list all possible outcomes and count the favorable ones.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following
The probability distribution of a random variable \( X \) is given below:
\( X \) | 1 | 2 | 4 | 2k | 3k | 5k |
---|---|---|---|---|---|---|
\( P(X) \) | \( \frac{1}{2} \) | \( \frac{1}{5} \) | \( \frac{3}{25} \) | \( \frac{1}{10} \) | \( \frac{1}{25} \) | \( \frac{1}{25} \) |