The total number of outcomes when two dice are rolled is \( 6 \times 6 = 36 \), as each die has 6 faces.
To find the favorable outcomes where the sum is 3, we look for all pairs of dice rolls that sum to 3: \[ (1,2), (2,1) \] Thus, there are 2 favorable outcomes. The probability is the ratio of favorable outcomes to total outcomes: \[ P(sum = 3) = \frac{2}{36} = \frac{1}{18} \] To find the probability of a specific sum in dice rolling, list all possible outcomes and count the favorable ones.
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :