To solve the problem, we are given two events based on the outcome of throwing two dice. The sample space consists of all ordered pairs \( (x, y) \) where \( x, y \in \{1, 2, 3, 4, 5, 6\} \).
1. Define the Events:
- Event \( A = \{(x, y) : x + y = 9\} \)
- Event \( B = \{(x, y) : x \neq 3\} \)
2. Total Number of Outcomes:
Since each die has 6 faces: total outcomes = \( 6 \times 6 = 36 \)
3. List Outcomes in A:
We list all pairs where the sum is 9:
\[
A = \{(3, 6), (4, 5), (5, 4), (6, 3)\}
\]
So, \( n(A) = 4 \)
4. List Outcomes in B:
All outcomes where \( x \neq 3 \). Since \( x = 3 \) appears in 6 outcomes (from (3,1) to (3,6)), there are \( 6 \times 6 - 6 = 30 \) outcomes.
So, \( n(B) = 30 \)
5. Find \( A \cap B \):
From \( A \), the only outcome with \( x = 3 \) is \( (3,6) \)
So \( A \cap B = A \setminus \{(3,6)\} = \{(4,5), (5,4), (6,3)\} \)
Therefore, \( n(A \cap B) = 3 \)
6. Check for Mutually Exclusive:
Events are mutually exclusive if \( A \cap B = \emptyset \)
But here, \( A \cap B \neq \emptyset \), so they are not mutually exclusive.
7. Check for Independence:
Events \( A \) and \( B \) are independent if:
\[
P(A \cap B) = P(A) \cdot P(B)
\]
Compute probabilities:
- \( P(A) = \frac{4}{36} = \frac{1}{9} \)
- \( P(B) = \frac{30}{36} = \frac{5}{6} \)
- \( P(A \cap B) = \frac{3}{36} = \frac{1}{12} \)
Now check:
\[
P(A) \cdot P(B) = \frac{1}{9} \cdot \frac{5}{6} = \frac{5}{54}
\]
But \( \frac{1}{12} = \frac{4.5}{54} \ne \frac{5}{54} \)
So \( P(A \cap B) \ne P(A) \cdot P(B) \)
8. Conclusion:
Events \( A \) and \( B \) are neither independent nor mutually exclusive.
Final Answer:
The events \( A \) and \( B \) are neither mutually exclusive nor independent.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following
Rupal, Shanu and Trisha were partners in a firm sharing profits and losses in the ratio of 4:3:1. Their Balance Sheet as at 31st March, 2024 was as follows:
(i) Trisha's share of profit was entirely taken by Shanu.
(ii) Fixed assets were found to be undervalued by Rs 2,40,000.
(iii) Stock was revalued at Rs 2,00,000.
(iv) Goodwill of the firm was valued at Rs 8,00,000 on Trisha's retirement.
(v) The total capital of the new firm was fixed at Rs 16,00,000 which was adjusted according to the new profit sharing ratio of the partners. For this necessary cash was paid off or brought in by the partners as the case may be.
Prepare Revaluation Account and Partners' Capital Accounts.
On the basis of the following hypothetical data, calculate the percentage change in Real Gross Domestic Product (GDP) in the year 2022 – 23, using 2020 – 21 as the base year.
Year | Nominal GDP | Nominal GDP (Adjusted to Base Year Price) |
2020–21 | 3,000 | 5,000 |
2022–23 | 4,000 | 6,000 |