Question:
Two coils of self-inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self-inductance of the combination will be:
Two coils of self-inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self-inductance of the combination will be:
Updated On: Feb 2, 2026
\(\frac{1}{L1 }\) + \(\frac{1}{L2}\) + \(\frac{1}{M}\)
- L1 + L2 + M
- L1 + L2 + 2M
- L1 + L2 – 2M
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The Correct Option is D
Solution and Explanation
Self-inductances are in series but their mutual inductances are linked oppositely so equivalent self-inductance
L = L1 + L2 – M – M
L = L1 + L2 – 2M
\(\therefore,\) The correct option is (D): \(L_1 + L_2 – 2M\)
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Concepts Used:
Electromagnetic Induction
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Formula:
The electromagnetic induction is mathematically represented as:-
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Where
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