Question:

Two charged spheres of \( -20\, \mu\text{C} \) and \( 60\, \mu\text{C} \) are kept at a certain distance. They are touched and kept again at the same distance. What is the ratio of force experienced before and after?

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After touching, charges redistribute equally on identical conductors. Use Coulomb’s law before and after.
Updated On: Apr 15, 2025
  • \( 1 : 3 \)
  • \( 3 : 1 \)
  • \( 2 : 1 \)
  • \( 1 : 2 \)
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The Correct Option is B

Solution and Explanation


Before touching: \[ F_1 = k \cdot \frac{|-20 \cdot 60| \times 10^{-12}}{r^2} = \frac{1200k}{r^2} \] After touching, total charge = \( 60 - 20 = 40\, \mu\text{C} \)
Shared equally: each gets \( 20\, \mu\text{C} \)
\[ F_2 = k \cdot \frac{(20)^2 \times 10^{-12}}{r^2} = \frac{400k}{r^2} \] Ratio: \[ \frac{F_1}{F_2} = \frac{1200}{400} = 3:1 \]
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