Two charged conducting spheres of radii a and b are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:
- \(\sqrt{ab}\)
- ab
- \(\frac{a}{b}\)
- \(\frac{b}{a}\)
The Correct Option is C
Solution and Explanation
The potential at the surface of a conducting sphere is given by:
\( V = \frac{Kq}{r} \).
Since the two spheres are connected, their potentials will be the same:
\[ \frac{Kq_1}{a} = \frac{Kq_2}{b}. \]
Simplifying:
\[ \frac{q_1}{q_2} = \frac{a}{b}. \]
Final Answer: \( \frac{a}{b} \).
Top Questions on Electrostatics
Match List - I with List - II:
List - I:
(A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
(C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).List - II:
(I) \( \frac{\sigma}{\epsilon_0} \)
(II) \( \frac{\sigma}{2\epsilon_0} \)
(III) 0
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