The magnetic moment (\( \mu \)) is related to the number of unpaired electrons (\( n \)) by the formula :
\( \mu = \sqrt{n(n+2)} \, \text{BM} \)
\( \mu = 6.06 \, \text{BM} \)
\( 6.06 = \sqrt{n(n+2)} \)
Squaring both sides :
\( 36.72 = n(n+2) \)
\( n \approx 5 \) (nearest integer).
Since Mn has 5 unpaired electrons, its oxidation state must be +2, as follows :
\( \text{Mn}^{2+} \Rightarrow x = +2. \)
The number of unpaired electrons is 5, and the oxidation state of Mn is +2.
So, Mn must be in +2 oxidation state (Mn+2)
\(⇒ 2 + (–6) = –x \)
\(⇒ –4 = –x \)
\(⇒ x = 4\)
The steam volatile compounds among the following are:

The structure of the major product formed in the following reaction is:

Let \( a \in \mathbb{R} \) and \( A \) be a matrix of order \( 3 \times 3 \) such that \( \det(A) = -4 \) and \[ A + I = \begin{bmatrix} 1 & a & 1 \\ 2 & 1 & 0 \\ a & 1 & 2 \end{bmatrix} \] where \( I \) is the identity matrix of order \( 3 \times 3 \).
If \( \det\left( (a + 1) \cdot \text{adj}\left( (a - 1) A \right) \right) \) is \( 2^m 3^n \), \( m, n \in \{ 0, 1, 2, \dots, 20 \} \), then \( m + n \) is equal to:
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.