

To identify chiral carbons, examine carbon atoms with four different substituents, which render them asymmetric:
Step 1. CH₃–CH₂–CH(NO₂)–COOH: The second carbon is chiral due to four distinct substituents.
Step 2. CH₃–CH₂–CHBr–CH₂–CH₃: The third carbon is chiral, as it has four different substituents.
Step 3. CH₃–CH(I)–CH₂–NO₂: The second carbon is chiral due to its four different groups.
Step 4. CH₃–CH₂–CH(OH)–CH₂OH: The third carbon is chiral, as it has four distinct substituents.
Step 5. CH₃–CH–CH(I)–C₂H₅: The second carbon is chiral due to four different substituents.
Thus, there are five compounds containing chiral carbons.
The Correct answer is: 5
Consider the following molecule (X).
The Structure X is? 
How many different stereoisomers are possible for the given molecule? 
Which of the following is true for the stereochemical relationship of the given structures (A-D)?

The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:

Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
If $ \theta \in [-2\pi,\ 2\pi] $, then the number of solutions of $$ 2\sqrt{2} \cos^2\theta + (2 - \sqrt{6}) \cos\theta - \sqrt{3} = 0 $$ is: