How many different stereoisomers are possible for the given molecule?
To determine the number of different stereoisomers for a given molecule, we must first understand the elements contributing to stereoisomerism. These typically include:
The total number of stereoisomers is calculated using the formula: 2n, where n equals the number of stereocenters (chiral centers + independent double bonds contributing to geometric isomerism).
Now, let's apply this to the problem:
1. **Identify Chiral Centers:**
Examine the molecule for any carbon atoms that have four distinct substituents. Assume the molecule in the image has two chiral centers.
2. **Double Bonds:**
Identify any carbon-carbon double bonds that can exhibit E/Z isomerism. Assume there are no such double bonds here.
3. **Calculate Total Stereoisomers:**
Using the formula, where n = 2 for the chiral centers:
22 = 4
Therefore, the total number of different stereoisomers possible for this molecule is 4.
Assertion (A): All naturally occurring \(\alpha\)-amino acids except glycine are optically active. Reason (R): Most naturally occurring amino acids have L-configuration.
(a) Define the following:
(i) Enantiomers
(ii) Racemic mixture
The CORRECT statement(s) regarding the given molecules is(are):
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).