How many different stereoisomers are possible for the given molecule?
To determine the number of different stereoisomers for a given molecule, we must first understand the elements contributing to stereoisomerism. These typically include:
The total number of stereoisomers is calculated using the formula: 2n, where n equals the number of stereocenters (chiral centers + independent double bonds contributing to geometric isomerism).
Now, let's apply this to the problem:
1. **Identify Chiral Centers:**
Examine the molecule for any carbon atoms that have four distinct substituents. Assume the molecule in the image has two chiral centers.
2. **Double Bonds:**
Identify any carbon-carbon double bonds that can exhibit E/Z isomerism. Assume there are no such double bonds here.
3. **Calculate Total Stereoisomers:**
Using the formula, where n = 2 for the chiral centers:
22 = 4
Therefore, the total number of different stereoisomers possible for this molecule is 4.
(a) Define the following:
(i) Enantiomers
(ii) Racemic mixture
The CORRECT statement(s) regarding the given molecules is(are):
Consider the following molecule (X).
The Structure X is?
Assertion (A): All naturally occurring \(\alpha\)-amino acids except glycine are optically active. Reason (R): Most naturally occurring amino acids have L-configuration.
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to:
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to: