To increase agricultural production and become self-sufficient with regard to food grains, the Green Revolution was initiated.
The Green Revolution refers to a series of agricultural innovations introduced in India during the 1960s and 1970s. Its main objective was to increase food grain production—especially of wheat and rice—and make the country self-sufficient in food. This included the adoption of high-yielding varieties (HYV) of seeds, greater use of fertilizers and pesticides, and the development of irrigation infrastructure.
The Green Revolution resulted in a major boost in agricultural output, particularly in Punjab, Haryana, and Uttar Pradesh. India achieved self-sufficiency in food grains and significantly reduced dependence on imports. This movement helped secure food stability, prevent famines, and strengthen rural economies.
Despite its success, the Green Revolution also brought challenges. Over-reliance on chemicals led to soil degradation, pollution, and health risks. Benefits were uneven—wealthier regions advanced faster, while others lagged behind. Additionally, emphasis on wheat and rice reduced agricultural biodiversity by sidelining coarse grains and pulses.
\[ \text{The Green Revolution was launched to increase agricultural production and make India self-sufficient in food grains.} \]
Complete the following chart :
Complete the following concept map :
Complete the following activity to prove that the sum of squares of diagonals of a rhombus is equal to the sum of the squares of the sides.
Given: PQRS is a rhombus. Diagonals PR and SQ intersect each other at point T.
To prove: PS\(^2\) + SR\(^2\) + QR\(^2\) + PQ\(^2\) = PR\(^2\) + QS\(^2\)
Activity: Diagonals of a rhombus bisect each other.
In \(\triangle\)PQS, PT is the median and in \(\triangle\)QRS, RT is the median.
\(\therefore\) by Apollonius theorem,
\[\begin{aligned} PQ^2 + PS^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(I)} \\ QR^2 + SR^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(II)} \\ \text{Adding (I) and (II),} \quad PQ^2 + PS^2 + QR^2 + SR^2 &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \\ &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \quad (\text{RT = PT}) \\ &= 4PT^2 + 4QT^2 \\ &= (\boxed{\phantom{X}})^2 + (2QT)^2 \\ \therefore \quad PQ^2 + PS^2 + QR^2 + SR^2 &= PR^2 + \boxed{\phantom{X}} \\ \end{aligned}\]