The equation of the line is given as:
\[
\frac{x-11}{12} = \frac{y-12}{13} = \frac{z+13}{14}.
\]
Let the common ratio be \( t \). Then, we can write the parametric equations for \( x \), \( y \), and \( z \) as:
\[
x = 12t + 11, \quad y = 13t + 12, \quad z = 14t - 13.
\]
Now, we substitute the coordinates \( x = 12, y = 13, z = 14 \) into these equations to verify the point:
\[
x = 12t + 11 \quad \Rightarrow \quad 12 = 12t + 11 \quad \Rightarrow \quad t = \frac{1}{12}.
\]
Substituting \( t = \frac{1}{12} \) into the equation for \( y \):
\[
y = 13t + 12 = 13 \times \frac{1}{12} + 12 = 13 \quad \text{(True)}.
\]
Substituting \( t = \frac{1}{12} \) into the equation for \( z \):
\[
z = 14t - 13 = 14 \times \frac{1}{12} - 13 = 14 \quad \text{(True)}.
\]
Thus, the line passes through the point (12, 13, 14). Hence, the correct answer is option (C).