Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across A and B, their readings are $V_1$, $V_2$ and $V_3$. 
Choose the correct option.
Applying Kirchhoff’s Voltage Law (KVL) across the loop: \(V_1 + V_2 - V_3 = 0 \implies V_1 + V_2 = V_3.\)
The Correct answer is: $V_1 + V_2 = V_3$
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: