We are given that there are 3 rotten apples and 7 good apples. 4 apples are drawn randomly without replacement. We need to find the value of \( 10(\mu^2 + \sigma^2) \), where \( \mu \) is the mean and \( \sigma^2 \) is the variance of the random variable \( X \), which represents the number of rotten apples drawn.
Step 1: Defining the Problem.
The number of rotten apples drawn, \( X \), follows a hypergeometric distribution, since we are drawing without replacement. The probability mass function (PMF) of \( X \) for a hypergeometric distribution is given by: \[ P(X = k) = \frac{\binom{3}{k} \binom{7}{4-k}}{\binom{10}{4}}, \] where: - \( 3 \) is the number of rotten apples,
- \( 7 \) is the number of good apples,
- \( 4 \) is the total number of apples drawn,
- \( k \) is the number of rotten apples drawn.
Step 2: Mean and Variance of Hypergeometric Distribution.
For a hypergeometric distribution, the mean \( \mu \) and variance \( \sigma^2 \) are given by the formulas: \[ \mu = \frac{nK}{N}, \quad \sigma^2 = \frac{nK(N-K)(N-n)}{N^2(N-1)}, \] where: - \( n = 4 \) (number of draws),
- \( K = 3 \) (total number of rotten apples),
- \( N = 10 \) (total number of apples).
Calculating the Mean \( \mu \): \[ \mu = \frac{4 \times 3}{10} = \frac{12}{10} = 1.2. \]
Calculating the Variance \( \sigma^2 \): \[ \sigma^2 = \frac{4 \times 3 \times (10 - 3) \times (10 - 4)}{10^2 \times (10 - 1)} = \frac{4 \times 3 \times 7 \times 6}{100 \times 9} = \frac{504}{900} = 0.56. \]
Step 3: Calculating \( 10(\mu^2 + \sigma^2) \). Now, calculate \( 10(\mu^2 + \sigma^2) \): \[ \mu^2 = (1.2)^2 = 1.44, \quad \sigma^2 = 0.56, \] \[ \mu^2 + \sigma^2 = 1.44 + 0.56 = 2. \] \[ 10(\mu^2 + \sigma^2) = 10 \times 2 = 20. \]
Thus, the value of \( 10(\mu^2 + \sigma^2) \) is \( 20 \), and the correct answer is option (4).
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
