Question:
Three helium atoms from carbon at high temperature due to fusion. Masses of helium and carbon nuclei a.m.u are 4.0002 and 12 respectively . Find energy released in the process
Three helium atoms from carbon at high temperature due to fusion. Masses of helium and carbon nuclei a.m.u are 4.0002 and 12 respectively . Find energy released in the process
Updated On: Apr 6, 2024
- 0.18 MeV
- 0.56 MeV
- 0.10 MeV
- 21.3 KeV
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The Correct answer is option is (B) : 0.56 MeV
Was this answer helpful?
0
0
Top Questions on Nuclear physics
- Define the term, ‘distance of closest approach’. A proton of 3.95 MeV energy approaches a target nucleus \( Z = 79 \) in head-on position. Calculate its distance of closest approach.
- CBSE CLASS XII - 2025
- Physics
- Nuclear physics
Mass Defect and Energy Released in the Fission of \( ^{235}_{92}\text{U} \)
When a neutron collides with \( ^{235}_{92}\text{U} \), the nucleus gives \( ^{140}_{54}\text{Xe} \) and \( ^{94}_{38}\text{Sr} \) as fission products, and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV) in the process.
Given:- Mass of \( ^{235}_{92}\text{U} \): \( m(^{235}_{92}\text{U}) = 235.04393 \, \text{u} \)
- Mass of \( ^{140}_{54}\text{Xe} \): \( m(^{140}_{54}\text{Xe}) = 139.92164 \, \text{u} \)
- Mass of \( ^{94}_{38}\text{Sr} \): \( m(^{94}_{38}\text{Sr}) = 93.91536 \, \text{u} \)
- Mass of neutron \( ^{1}_0n \): \( m(^{1}_0n) = 1.00866 \, \text{u} \)
- Conversion factor: \( 1 \, \text{u} = 931 \, \text{MeV}/c^2 \)
- CBSE CLASS XII - 2025
- Physics
- Nuclear physics
- Two statements are given, one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.
% Assertion Assertion (A): During the formation of a nucleus, the mass defect produced is the source of the binding energy of the nucleus.
Reason (R): For all nuclei, the value of binding energy per nucleon increases with mass number.
- CBSE CLASS XII - 2025
- Physics
- Nuclear physics
- Differentiate between ‘nuclear fission’ and ‘nuclear fusion’. Briefly discuss one example of each.
- CBSE CLASS XII - 2025
- Physics
- Nuclear physics
- An alpha particle and a deuterium ion are accelerated through the same potential difference. These are then directed towards a target nucleus to make a head-on collision. It is observed that their distance of closest approach is the same. Justify it theoretically.
- CBSE CLASS XII - 2025
- Physics
- Nuclear physics
View More Questions
Questions Asked in JEE Main exam
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
- JEE Main - 2025
- Number Systems
- The square of the distance of the point \(\left( \frac{15}{7}, \frac{32}{7}, 7 \right)\) from the line \(\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}\) in the direction of the vector \(\mathbf{i} + 4\mathbf{j} + 7\mathbf{k}\) is:
- JEE Main - 2025
- 3D Geometry
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:
- JEE Main - 2025
- Binomial theorem
- If the mean and the variance of 6, 4, 8, 8, b, 12, 10, 13 are 9 and 9.25 respectively, then $ a + b + ab $ is equal to:
- JEE Main - 2025
- Variance and Standard Deviation
- Consider the following elements In, Tl, Al, Pb, and Ge. The most stable oxidation states of elements with highest and lowest first ionisation enthalpies, respectively, are:
- JEE Main - 2025
- Periodic properties
View More Questions