The weight percentage of hydrogen in Q, formed in the following reaction sequence, is ________.
[Given : Atomic mass of H = 1, C = 12, N = 14, O = 16, S = 32, Cl = 35]
[Given : Atomic mass of H = 1, C = 12, N = 14, O = 16, S = 32, Cl = 35]
Correct Answer: 1.31
Solution and Explanation
The molecular weight of \( C_8H_8O_2 \) is calculated as:
Molecular weight = \( 12 \times 8 + 1 \times 8 + 16 \times 2 = 96 + 8 + 32 = 136 \)
Next, we calculate the moles of product \( D \) formed:
Moles of product \( D \) = \( \frac{15}{3} \times 0.8 \times 0.5 = \frac{3}{3} = 1 \)
Therefore, the weight of product \( D \) is:
Weight of product \( D \) = \( 1 \times 136 = 136 \, \text{g} \)
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Concepts Used:
Alcohols, Phenols, and Ethers - Chemical Reactions
The reaction of alcohols:
- Reaction with Metal
- Reaction with Halides
- Reaction with HNO3
- Reaction with Carboxylic Acid (Esterification)
- Dehydration of Alcohol
- Haloform Reaction
The reaction of phenols:
- Formation of Ester
- Hydrogenation
- Oxidation of Quinones
- Electrophilic Substitution
- Halogenation
The reaction of ethers:
- Contact with Air
- Halogenation of Ether
- Electrophilic Substitution Reaction
Read More: Alcohols, Phenols, and Ethers