Question

The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?

• A. 13 m
• B. 30 m
• C. 11 m
• D. 10 m

Hint:

In velocity-time graphs, the distance covered is simply the area under the graph. Use the appropriate geometry (triangles, rectangles, trapezoids) to calculate the area.

Answer 1

The Correct Option is A

The distance covered by an object is given by the area under the velocity-time graph. Here, the graph shows a combination of trapezoidal and rectangular areas. The total area under the graph between \( t = 0 \) and \( t = 4 \) represents the distance traveled. By calculating the area from the graph: \[ \text{Distance} = \text{Area under the graph} = 13 \, \text{m} \]