A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by x = 40 + 12t - t3 How long would the particle travel before coming to rest ?
Particle Coming to Rest: To find when the particle comes to rest, we need to find the time at which the velocity becomes zero.
The velocity function is given as v = 40 + 12t - t3.
Set v = 0 : 0 = 40 + 12t - t3.
Solving this equation for t, we find t = 4 seconds.
To find the distance traveled before coming to rest, use the equation for displacement:
x = \(\int\)(0 to 4) v \(dt\).
Calculating the integral, and we find that the particle travels a distance of 56 meters.
Therefore, the correct option is (C): 56 m
The displacement x of a particle varies with time t as \(x=ae^{- \alpha t} + be ^{\beta t}\), where \(a,b,\) \(\alpha\) and \(\beta\) are positive constants. The velocity of the particle will:
Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is \(T_1\) and that at the right junction is \(T_2\). The ratio \(T_1 / T_2\) is
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Linear motion is also known as the Rectilinear Motion which are of two types: