A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by x = 40 + 12t - t3 How long would the particle travel before coming to rest ?
Particle Coming to Rest: To find when the particle comes to rest, we need to find the time at which the velocity becomes zero.
The velocity function is given as v = 40 + 12t - t3.
Set v = 0 : 0 = 40 + 12t - t3.
Solving this equation for t, we find t = 4 seconds.
To find the distance traveled before coming to rest, use the equation for displacement:
x = \(\int\)(0 to 4) v \(dt\).
Calculating the integral, and we find that the particle travels a distance of 56 meters.
Therefore, the correct option is (C): 56 m
The displacement x of a particle varies with time t as \(x=ae^{- \alpha t} + be ^{\beta t}\), where \(a,b,\) \(\alpha\) and \(\beta\) are positive constants. The velocity of the particle will:
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
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Linear motion is also known as the Rectilinear Motion which are of two types: