The acceleration due to gravity at height \( h \) from the Earth's surface is given by:
\( g_h = \frac{g_0}{(1 + \frac{h}{R})^2} .\)
Substituting \( h = \frac{R}{2} \),
we get: \( g_h = \frac{9.8}{2.25} = 4.4 \, \text{m/s}^2 \).
In the given graph, \( E_a \) for the reverse reaction will be