Question:

The value of acceleration due to gravity at a height equal to half the radius of the Earth, from its surface

Updated On: Dec 26, 2024
  • 4.4 m/s²
  • 6.5 m/s²
  • Zero
  • 9.8 m/s²
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The Correct Option is A

Solution and Explanation

The acceleration due to gravity at height \( h \) from the Earth's surface is given by:
\( g_h = \frac{g_0}{(1 + \frac{h}{R})^2} .\) 

Substituting \( h = \frac{R}{2} \), 
we get: \( g_h = \frac{9.8}{2.25} = 4.4 \, \text{m/s}^2 \).

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