The acceleration due to gravity at height \( h \) from the Earth's surface is given by: \( g_h = \frac{g_0}{(1 + \frac{h}{R})^2} .\)
Substituting \( h = \frac{R}{2} \), we get: \( g_h = \frac{9.8}{2.25} = 4.4 \, \text{m/s}^2 \).