Question

The total number of ‘Sigma’ and Pi bonds in 2 formylhex-4-enoic acid is ____.

Answer 1

Correct Answer: 22

Bond Analysis of 2-formylhex-4-enoic acid 

Compound Structure: 

The compound 2-formylhex-4-enoic acid has the molecular structure represented as:

\(H–O–C(=O)–CH(CHO)–CH_2–CH=CH–CH_3\)

Where the numbering of carbon atoms is as follows: \(C_1\) to \(C_6\).

Bond Analysis:

Each single bond is a \(\sigma\) (sigma) bond, and each double bond consists of one \(\sigma\) and one \(\pi\) (pi) bond.

• There are 19 sigma (\(\sigma\)) bonds in total.
• There are 3 pi (\(\pi\)) bonds in total.

Detailed Explanation:

1. The molecule contains both a –COOH (carboxylic acid) group and a –CHO (formyl) group.

2. The C=O bonds in both groups contribute two \(\pi\) bonds.

3. The C=C double bond at position 4–5 adds one more \(\pi\) bond.

4. Adding all sigma and pi bonds, we get:

\[\sigma\text{-bonds} = 19, \quad \pi\text{-bonds} = 3\]

Final Answer:

\[\boxed{\sigma = 19, \quad \pi = 3}\]