The electric flux \( \Phi_E \) through a closed surface surrounding an electric dipole is given by Gauss’s Law:
\( \Phi_E = \frac{Q_{\text{enc}}}{\epsilon_0} \) where \( Q_{\text{enc}} \) is the net charge enclosed by the surface and \( \epsilon_0 \) is the permittivity of free space.
Since an electric dipole consists of two equal and opposite charges, the total charge enclosed by the surface is zero.
Therefore, the total electric flux through the surface is also zero:\( \Phi_E = 0 \)
A line charge of length \( \frac{a}{2} \) is kept at the center of an edge BC of a cube ABCDEFGH having edge length \( a \). If the density of the line is \( \lambda C \) per unit length, then the total electric flux through all the faces of the cube will be : (Take \( \varepsilon_0 \) as the free space permittivity)
Two charges of \(5Q\) and \(-2Q\) are situated at the points \((3a, 0)\) and \((-5a, 0)\) respectively. The electric flux through a sphere of radius \(4a\) having its center at the origin is: