To solve the problem, we need to find the length of the wire connecting the tops of two poles with different heights, where the wire makes an angle of $30^\circ$ with the horizontal.
1. Understanding the Setup:
- Height of first pole = 20 m
- Height of second pole = 14 m
- Vertical difference between the tops = $20 - 14 = 6$ m
- Angle between the wire and horizontal = $30^\circ$
2. Using Trigonometry (Sine Function):
We model the situation as a right triangle where:
- Opposite side = vertical difference = 6 m
- Hypotenuse = length of the wire (to be found)
- Angle with horizontal = $30^\circ$
Using $ \sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} $, we have:
$ \sin 30^\circ = \frac{6}{\text{Length}} $
3. Solving for the Length:
$ \sin 30^\circ = \frac{1}{2} $
So, $ \frac{1}{2} = \frac{6}{\text{Length}} $
$ \text{Length} = 6 \times 2 = 12 $ m
Final Answer:
The length of the wire is $ \mathbf{12 \, \text{m}} $.