Step 1: Use trigonometric relation.
We are given:
Distance from wall (adjacent side) = \(6\) ft
Angle with ground = \(60^\circ\)
We need the hypotenuse (ladder length)
From \(\cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}\), \[ \cos 60^\circ = \frac{6}{\text{hypotenuse}} \Rightarrow \frac{1}{2} = \frac{6}{L} \Rightarrow L = 12 \]
The shadow of a tower on level ground is $30\ \text{m}$ longer when the sun's altitude is $30^\circ$ than when it is $60^\circ$. Find the height of the tower. (Use $\sqrt{3}=1.732$.)