Question:
The system of equations:
\[
x + y + z = 6, \quad x + 2y + 5z = 9, \quad x + 5y + \lambda z = \mu,
\]
has no solution if:
The system of equations:
\[
x + y + z = 6, \quad x + 2y + 5z = 9, \quad x + 5y + \lambda z = \mu,
\]
has no solution if:
Updated On: Jan 23, 2025
- Increase
- Decrease
- \( H^+ \) increases, \( OH^- \) decreases
- Remains constant
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The Correct Option is C
Solution and Explanation
For a system of linear equations to have no solution, the determinant of the coefficient matrix should be zero. We use the conditions involving \( \lambda \) and \( \mu \) to find the necessary conditions for no solution.
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