To solve this problem, we need to determine the number of sigma ($\sigma$) and pi ($\pi$) bonds in the given structure of Hex-1,3-dien-5-yne, which is $CH_2=CH-CH=CH-CH_2-C \equiv CH$.
1. Analyzing the Structure:
We need to count each $\sigma$ and $\pi$ bond in the molecule.
2. Counting Sigma Bonds:
Total $\sigma$ bonds = 1 + 1 + 1 + 1 + 2 + 1 + 1 + 2 + 1 = 11
3. Counting Pi Bonds:
Total $\pi$ bonds = 1 + 1 + 2 = 4
4. Calculating the Sum:
Sum of $\sigma$ and $\pi$ bonds = 11 + 4 = 15
Final Answer:
The sum of sigma ($\sigma$) and pi ($\pi$) bonds is 15.
The product (P) formed in the following reaction is:
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: