Question:

The sum of first 50 terms of the A.P. \( 2, 4, 6, 8, \dots \) is:

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For the sum of an arithmetic sequence: \[ S_n = \frac{n}{2} (2a + (n-1)d) \]
Updated On: Oct 27, 2025
  • \( 2500 \)
  • \( 2550 \)
  • \( 2005 \)
  • \( 2000 \)
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The Correct Option is B

Solution and Explanation

The sum of the first \( n \) terms of an arithmetic progression is given by:
\[ S_n = \frac{n}{2} (2a + (n-1)d) \] Here, \( a = 2 \), \( d = 4 - 2 = 2 \), and \( n = 50 \):
\[ S_{50} = \frac{50}{2} (2(2) + (50-1) \cdot 2) \] \[ = 25 (4 + 98) = 25 \times 102 = 2550 \]
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