Question:

The standard reduction potential at 298 K for the following half cells are given below  
NO − 3 3 − + 4H+ + 3e- → NO(g) +2H2O E0 = 0.97V 
\(V^{2+} (aq) + 2e^-→V\)           E0 = -1.19V 
\(Fe^{3+}(aq) + 3e^- → Fe\)        E0 = -0.04V 
\(Ag^+ (aq) + e^- → Ag(s)\)      E0 = 0.80V 
\(Au^{3+}(aq)+3e^-→Au(s)\) E0 = 1.40V 
The number of metal(s) which will be oxidized by  \(N0^-_3\) Oin aqueous solution is______.

Updated On: Apr 23, 2024
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Correct Answer: 3

Solution and Explanation

The correct answer is: 3
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