Question:

The 'spin only' magnetic moment value of \(MO_4^{2-}\) is ____ \(\text{BM}\). (Where \(M\) is a metal having least metallic radii among \(\text{Sc, Ti, V, Cr, Mn, Zn}\)). \([ \text{Given atomic number: Sc = 21, Ti = 22, V = 23, Cr = 24, Mn = 25, Zn = 30} ]\)

Updated On: Nov 24, 2024
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 0

Solution and Explanation

Among the given elements, Cr has the least metallic radii. The CrO$_4^{2-}$ ion has Cr$^{6+}$, which has a $d^0$ configuration (diamagnetic).
The spin-only magnetic moment:
\[\mu = \sqrt{n(n+2)} \, \text{BM},\]
where $n = 0$.
Final Answer:
\[0 \, \text{BM}.\]

Was this answer helpful?
0
0