Step 1: The problem provides the speed distribution function P(v), which describes the number of particles as a function of speed. The graph indicates that the distribution P(v) is nonzero for speeds between 0 and 2v_0, and zero for speeds higher than 2v_0.
Step 2: To determine how many particles have speeds between 1.2v_0 and 1.8v_0, we calculate the area under the curve from 1.2v_0 to 1.8v_0.
Step 3: From the given graph, the area between these two speeds is 0.4 of the total number of particles N.
Step 4: Therefore, the number of particles with speeds in this range is 0.4N.
To find the number of gas particles with speeds between \(1.2v_0\) and \(1.8v_0\), we look at the area under the speed distribution curve \(P(v)\) in that range.
The total area under the curve from \(0\) to \(2v_0\) represents the entire sample of particles, which is \(N\).
From the graph, the area between \(1.2v_0\) and \(1.8v_0\) accounts for 40% of the total area.
Therefore, the number of particles in this speed range is:
\[ \text{Number of particles} = 0.4N \]
Final Answer: 0.4 N
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of: