



To solve this question, we need to determine the products of the reaction between 2,4-dinitrofluorobenzene and hydrazine.
Step 1: Understanding the Reaction
2,4-dinitrofluorobenzene is a compound with strong electron-withdrawing nitro groups at the 2 and 4 positions on a benzene ring, which activates the fluorine for nucleophilic substitution.
Upon reaction with hydrazine (NH2NH2), the nucleophilic nitrogen on the hydrazine attacks the carbon with the fluorine, displacing the fluoride ion. This reaction is characteristic and leads to the formation of a hydrazone linkage.
Step 2: Identifying the Yellow Orange Solid X
The product of this reaction is known to be a 2,4-dinitrophenylhydrazone, a yellow-orange solid. This compound, referred to as X in the question, is known for its intense coloration, which is used in chemical analysis.
Step 3: Determining the Functional Group G
The functional group that 2,4-dinitrophenylhydrazone helps identify is the carbonyl group (C=O), commonly found in aldehydes and ketones. This is because hydrazone derivatives form selectively when carbonyl compounds react with hydrazine derivatives.
In the context of this reaction, hydrazines are typical reagents for testing carbonyl functionalities, and the formation of 2,4-dinitrophenylhydrazone derivatives confirms the presence of such a group.
Conclusion
Thus, the compounds X and G are identified as 2,4-dinitrophenylhydrazone and carbonyl group, respectively.


The compound(s) that shows(show) positive haloform test is(are) 
One mole of a monoatomic ideal gas starting from state A, goes through B and C to state D, as shown in the figure. Total change in entropy (in J K\(^{-1}\)) during this process is ............... 
The number of chiral carbon centers in the following molecule is ............... 
A tube fitted with a semipermeable membrane is dipped into 0.001 M NaCl solution at 300 K as shown in the figure. Assume density of the solvent and solution are the same. At equilibrium, the height of the liquid column \( h \) (in cm) is ......... 
An electron at rest is accelerated through 10 kV potential. The de Broglie wavelength (in A) of the electron is .............