In the given reaction, naphthalene is treated with chromium trioxide (\text{CrO}_3) in the presence of glacial acetic acid. This is an oxidative reaction where naphthalene is oxidized by chromium trioxide, which acts as an oxidizing agent. Let's analyze the reaction step-by-step:
- Chromium trioxide is a strong oxidizing agent commonly used for converting aromatic compounds into quinones.
- Naphthalene is a polycyclic aromatic hydrocarbon that can undergo oxidation when exposed to strong oxidizing agents.
- In the presence of glacial acetic acid, an organic solvent, chromium trioxide facilitates the oxidation of naphthalene into naphthoquinones.
- The specific oxidation product formed most commonly when naphthalene reacts with chromium trioxide is naphthalene-1,4-dione, also known as 1,4-naphthoquinone.
Let's understand why this specific quinone is formed:
- Naphthalene-1,4-dione is formed due to the preferential oxidation at the 1 and 4 positions in the naphthalene ring, which is stabilized by resonance structures.
- The oxidation involves the removal of two hydrogen atoms from naphthalene, resulting in the formation of two carbonyl groups (C=O) at these positions.
- Naphthalene-1,4-dione is a stable compound due to the conjugated system of double bonds and carbonyl groups in its structure.
Among the given options, Naphthalene-1.4-dione accurately describes the product of the reaction between naphthalene and chromium trioxide in glacial acetic acid:
- Naphthalene-1.4-dione: The correct option as explained above.
- 4-Hydroxynaphthalen-1(4H)-one: Incorrect, as it suggests a hydroxylation rather than oxidation to a quinone.
- Napthanelen-1.2-dione: Incorrect, as it implies oxidation at 1,2-positions which is less favorable.
- 1-Hydroxynaphthalen-2(1H)-one: Incorrect, as it represents a hydroxylation rather than oxidation.
Therefore, the correct answer is Naphthalene-1.4-dione.