The ratio of number of oxygen atoms to bromine atoms in the product $Q$ is ___ $\times 10^{-1}$.
The ratio of number of oxygen atoms to bromine atoms in the product $Q$ is ___ $\times 10^{-1}$.
Correct Answer: 15
Solution and Explanation
The initial compound with \( \text{OC}_2\text{H}_5 \) undergoes nitration to introduce a \( \text{NO}_2 \) group, yielding intermediate \( P \).
\[ \text{OC}_2\text{H}_5 \xrightarrow{\text{HNO}_3, \text{H}_2\text{SO}_4} \text{OC}_2\text{H}_5\text{NO}_2 \]
Bromination of \( P \) in the presence of Fe introduces two bromine atoms on the aromatic ring, resulting in product \( Q \).
\[ \text{OC}_2\text{H}_5\text{NO}_2 \xrightarrow{\text{2 Br}_2, \text{Fe}} \text{Br-OC}_2\text{H}_5\text{NO}_2\text{Br} \]
Count the number of oxygen and bromine atoms in product \( Q \):
- Oxygen atoms: 3 (one from \( \text{OC}_2\text{H}_5 \) and two from \( \text{NO}_2 \))
- Bromine atoms: 2
The ratio of oxygen to bromine atoms in \( Q \) is:
\[ \frac{3}{2} \times 10^{-1} = 15 \times 10^{-1} \]
Answer: 15
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