Question:

The ratio of angular velocity of two satellites at a distance $ r $ and $ 2r $ from the centre of the earth is:

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The angular velocity of a satellite is inversely proportional to the 3/2 power of the radius of its orbit.
Updated On: Apr 28, 2025
  • \( 1:1 \)
  • \( 1:2 \)
  • \( 2:1 \)
  • \( 4:1 \)
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The Correct Option is C

Solution and Explanation

The angular velocity \( \omega \) of a satellite is given by: \[ \omega = \sqrt{\frac{GM}{r^3}} \] Where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( r \) is the radius of the orbit. For two satellites at distances \( r \) and \( 2r \), the ratio of angular velocities is: \[ \frac{\omega_1}{\omega_2} = \frac{\sqrt{\frac{GM}{r^3}}}{\sqrt{\frac{GM}{(2r)^3}}} = \frac{\sqrt{1}}{\sqrt{\frac{1}{8}}} = 2 \]
Thus, the ratio of angular velocities is \( 2:1 \).
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