Question:
The product , which is not obtained during the electrolysis of brine solution is
The product , which is not obtained during the electrolysis of brine solution is
Updated On: Oct 18, 2024
- \(cl_2\)
- H2
- HCl
- NaOH
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The correct option is(B): H2
Was this answer helpful?
0
1
Top Questions on Electrolysis
- What is the mass ratio of the gases collected at the anode and cathode?
- CBSE Class X - 2024
- Science
- Electrolysis
- Why is the electrolysis of water called a decomposition reaction?
- CBSE Class X - 2024
- Science
- Electrolysis
- Name the gases collected at the anode and cathode.
- CBSE Class X - 2024
- Science
- Electrolysis
- Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is (Given : Molar mass of Cu : 63 g mol–1 , 1 F = 96487 C)
- NEET (UG) - 2024
- Chemistry
- Electrolysis
- $\text{A constant current was passed through a solution of AuCl}_4^- \text{ ion between gold electrodes. After a} \\\text{period of 10.0 minutes, the increase in mass of cathode was 1.314 g. The total charge passed} \\$$\text{through the solution is \_\_\_\_\_\_\_\_} \times 10^{-2} \, \text{F.} \\$$\text{(Given atomic mass of Au = 197)}$
- JEE Main - 2024
- Chemistry
- Electrolysis
View More Questions
Questions Asked in JEE Main exam
- A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
- JEE Main - 2024
- Electromagnetic induction
- Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation \( i = i_0 \sin \omega t \), where \( i_0 = 5 \, \text{A} \) and \( \omega = 50\pi \, \text{rad/s} \). The maximum value of emf in the second coil is \( \frac{\pi}{\alpha} \). The value of \( \alpha \) is ______.
- JEE Main - 2024
- Electromagnetic induction
- The 20th term from the end of the progression \[ 20, 19, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \ldots, -129 \frac{1}{4} \] is:
- JEE Main - 2024
- Arithmetic Progression
- We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01M & 0.001 M, respectively. The value of vant’ Haft factor (i) for these solutions will be in the order.
- JEE Main - 2024
- Colligative Properties
- $\Delta_{vap}H^\circ$ for water is $+40.49 \, \text{kJ mol}^{-1}$ at 1 bar and $100^\circ\text{C}$. Change in internal energy for this vaporisation under same condition is .............. kJ mol$^{-1}$. (Integer answer)
(Given R = 8.3 J K$^{-1}$ mol$^{-1}$)- JEE Main - 2024
- Enthalpy change
View More Questions