The product (P) formed in the following reaction is: 




To solve this problem, we need to identify the product of a Clemmensen reduction on the given compound.
1. Understanding Clemmensen Reduction:
The Clemmensen reduction uses zinc amalgam (Zn-Hg) and hydrochloric acid (HCl) to reduce carbonyl groups (ketones and aldehydes) to alkane groups (-CH₂- or -CH₃).
2. Identifying Reactive Groups:
In the starting material, we have a ketone, an aldehyde, and an ester group. Clemmensen reduction affects ketones and aldehydes, but not esters.
3. Predicting Reduction Products:
The ketone will be reduced to a -CH₂- group. The aldehyde will be reduced to a -CH₃ group. The ester will remain unchanged.
4. Evaluating the Options:
We need to choose the option where the ketone is reduced to -CH₂-, the aldehyde is reduced to -CH₃, and the ester remains an ester.
5. Selecting the Correct Answer:
Option (2) correctly shows the ketone reduced to -CH₂-, the aldehyde reduced to -CH₃, and the ester group unchanged.
Final Answer:
The correct product (P) is (2).
Choose the correct set of reagents for the following conversion:
When
undergoes intramolecular aldol condensation, the major product formed is:

Choose the correct option for structures of A and B, respectively:

Consider the following reaction occurring in the blast furnace. \[ {Fe}_3{O}_4(s) + 4{CO}(g) \rightarrow 3{Fe}(l) + 4{CO}_2(g) \] ‘x’ kg of iron is produced when \(2.32 \times 10^3\) kg \(Fe_3O_4\) and \(2.8 \times 10^2 \) kg CO are brought together in the furnace.
The value of ‘x’ is __________ (nearest integer).
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
X g of benzoic acid on reaction with aqueous \(NaHCO_3\) release \(CO_2\) that occupied 11.2 L volume at STP. X is ________ g.
Standard entropies of \(X_2\), \(Y_2\) and \(XY_5\) are 70, 50, and 110 J \(K^{-1}\) mol\(^{-1}\) respectively. The temperature in Kelvin at which the reaction \[ \frac{1}{2} X_2 + \frac{5}{2} Y_2 \rightarrow XY_5 \quad \Delta H = -35 \, {kJ mol}^{-1} \] will be at equilibrium is (nearest integer):