Question:

The points of the ellipse $16x^2 + 9y^2 = 400$ at which the ordinate decreases at the same rate at which the abscissa increases is/are given by

Updated On: Apr 23, 2024
  • $\left(3, \frac{16}{3}\right)\&\left(-3, \frac{-16}{3}\right)$
  • $\left(3, \frac{-16}{3}\right)\&\left(-3, \frac{16}{3}\right)$
  • $\left(\frac{1}{16}, \frac{1}{9}\right)\& \left(-\frac{1}{16}, -\frac{1}{9}\right)$
  • $\left(\frac{1}{16}, -\frac{1}{9}\right)\& \left(-\frac{1}{16}, \frac{1}{9}\right)$
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The Correct Option is A

Solution and Explanation

$\frac{x^{2}}{25}+\frac{y^{2}}{\frac{400}{9}}=1$
$\left(5\,cos\theta, \frac{20}{3}sin\theta\right)$
$x=5cos\theta, y=\frac{20}{3}sin\theta$
$\frac{dx}{d\theta}=-5\,sin\,\theta, \frac{dy}{d\theta}=\frac{20}{3}\,cos\,\theta$
$\frac{dx}{d\theta}=-\frac{dy}{d\theta}$
$-5sin\theta=-\frac{20}{3}cos\,\theta$
$tan\theta=4/3 \Rightarrow cos\theta=3/5$ or $-3/5$
$sin\theta=4/5$ or $-4/5$
Points are $\left(3, \frac{16}{3}\right)$ and $\left(-3, \frac{-16}{3}\right)$
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Concepts Used:

Ellipse

Ellipse Shape

An ellipse is a locus of a point that moves in such a way that its distance from a fixed point (focus) to its perpendicular distance from a fixed straight line (directrix) is constant. i.e. eccentricity(e) which is less than unity

Properties 

  • Ellipse has two focal points, also called foci.
  • The fixed distance is called a directrix.
  • The eccentricity of the ellipse lies between 0 to 1. 0≤e<1
  • The total sum of each distance from the locus of an ellipse to the two focal points is constant
  • Ellipse has one major axis and one minor axis and a center

Read More: Conic Section

Eccentricity of the Ellipse

The ratio of distances from the center of the ellipse from either focus to the semi-major axis of the ellipse is defined as the eccentricity of the ellipse.

The eccentricity of ellipse, e = c/a

Where c is the focal length and a is length of the semi-major axis.

Since c ≤ a the eccentricity is always greater than 1 in the case of an ellipse.
Also,
c2 = a2 – b2
Therefore, eccentricity becomes:
e = √(a2 – b2)/a
e = √[(a2 – b2)/a2] e = √[1-(b2/a2)]

Area of an ellipse

The area of an ellipse = πab, where a is the semi major axis and b is the semi minor axis.

Position of point related to Ellipse

Let the point p(x1, y1) and ellipse

(x2 / a2) + (y2 / b2) = 1

If [(x12 / a2)+ (y12 / b2) − 1)]

= 0 {on the curve}

<0{inside the curve}

>0 {outside the curve}