- Torque is given by \( {Torque} = {Force} \times {Distance} \), so its dimensional formula is \( [M L^2 T^{-2}] \).
- Energy is given by \( {Energy} = {Force} \times {Distance} \), so its dimensional formula is also \( [M L^2 T^{-2}] \). Hence, Torque and Energy have the same dimensions, and the correct answer is not option (1). Let's check other options to make sure.
- Pressure is given by \( {Pressure} = \frac{{Force}}{{Area}} \), so its dimensional formula is \( [M L^{-1} T^{-2}] \).
- Young’s modulus is given by \( {Young's modulus} = \frac{{Stress}}{{Strain}} \), and its dimensional formula is also \( [M L^{-1} T^{-2}] \). Thus, Pressure and Young’s modulus have the same dimensions.
- Angular momentum has dimensions \( [M L^2 T^{-1}] \) and Planck's constant has dimensions \( [M L^2 T^{-1}] \), so they have the same dimensions.
- Surface tension has dimensions \( [M T^{-2}] \) and impulse has dimensions \( [M L T^{-1}] \), so they do not have the same dimensions. Thus, the correct answer is option (1).
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: