Step 1: Use magnification formula for lenses. \[ m = \frac{-v}{u} \] Step 2: Given that image is formed at twice the distance of object from lens.
So, if object distance = \( u \), then image distance \( v = -2u \) (real and on opposite side).
Step 3: Calculate magnification. \[ m = \frac{-(-2u)}{u} = \frac{2u}{u} = 2 \] So, the magnification is \( 2 \). Since the image is real and inverted, but sign conventions were carefully handled, the magnitude remains positive here.
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
A solid glass sphere of refractive index $ n = \sqrt{3} $ and radius $ R $ contains a spherical air cavity of radius $ \dfrac{R}{2} $, as shown in the figure. A very thin glass layer is present at the point $ O $ so that the air cavity (refractive index $ n = 1 $) remains inside the glass sphere. An unpolarized, unidirectional and monochromatic light source $ S $ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $ O $ and is fully polarized, then the angle of incidence at the inner surface of the glass sphere is $ \theta $. The value of $ \sin \theta $ is ____