A NAND gate produces an output that is the negation of the AND gate output. The output (\( Y \)) is given by: \[ Y = \overline{A \cdot B}, \] where \( A \) and \( B \) are the inputs to the NAND gate. The truth table for a NAND gate is as follows:
Step-by-Step Analysis of the Inputs and Outputs: - When both \( A = 0 \) and \( B = 0 \), the output \( Y = 1 \).
- When \( A = 0 \) and \( B = 1 \), the output \( Y = 1 \). - When \( A = 1 \) and \( B = 0 \), the output \( Y = 1 \).
- When both \( A = 1 \) and \( B = 1 \), the output \( Y = 0 \).
Now analyze the given input waveforms for \( A \) and \( B \):
1. For each interval where \( A \) and \( B \) are given, calculate \( A \cdot B \).
2. Take the negation (\( \overline{A \cdot B} \)) to find the output \( Y \).
From the given inputs and truth table, the output waveform matches Option (2).
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
The logic gate equivalent to the circuit given in the figure is
The logic gate equivalent to the combination of logic gates shown in the figure is
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: