A NAND gate produces an output that is the negation of the AND gate output. The output (\( Y \)) is given by: \[ Y = \overline{A \cdot B}, \] where \( A \) and \( B \) are the inputs to the NAND gate. The truth table for a NAND gate is as follows:
Step-by-Step Analysis of the Inputs and Outputs: - When both \( A = 0 \) and \( B = 0 \), the output \( Y = 1 \).
- When \( A = 0 \) and \( B = 1 \), the output \( Y = 1 \). - When \( A = 1 \) and \( B = 0 \), the output \( Y = 1 \).
- When both \( A = 1 \) and \( B = 1 \), the output \( Y = 0 \).
Now analyze the given input waveforms for \( A \) and \( B \):
1. For each interval where \( A \) and \( B \) are given, calculate \( A \cdot B \).
2. Take the negation (\( \overline{A \cdot B} \)) to find the output \( Y \).
From the given inputs and truth table, the output waveform matches Option (2).
Consider the following logic circuit.
The output is Y = 0 when :
An \( \alpha \) particle is scattered from an Au target at rest as shown in the figure. \( D_1 \) and \( D_2 \) are the detectors to detect the scattered \( \alpha \) particle at an angle \( \theta \) and along the beam direction, respectively, as shown. The signals from \( D_1 \) and \( D_2 \) are converted to logic signals and fed to logic gates. When a particle is detected, the signal is 1 and is 0 otherwise. Which one of the following circuits detects the particle scattered at the angle \( \theta \) only?
A logic gate circuit is shown in the figure below. The correct combination for the input \( (P, Q) \) for which the output \( T = 1 \) is:
Match List-I with List-II.
Choose the correct answer from the options given below :