To find the order and degree:
- The order is the highest derivative present in the equation. Here, the highest derivative is $\frac{d^2 y}{dx^2}$, so the order is 2.
- The degree is the power of the highest order derivative after removing all fractional powers and roots. The term $\left( \frac{d^2 y}{dx^2} \right)^2$ appears inside a square again, making it of power 2 × 2 = 4 originally.
But we observe it appears as $\left[ \left( \frac{d^2 y}{dx^2} \right)^2 - 1 \right]^2$.
So the degree with respect to the highest derivative (i.e., $d^2y/dx^2$) is 2.
Camphor is a waxy, colourless solid with strong aroma that evaporates through the process of sublimation if left in the open at room temperature.
(Cylindrical-shaped Camphor tablets) A cylindrical camphor tablet whose height is equal to its radius (r) evaporates when exposed to air such that the rate of reduction of its volume is proportional to its total surface area. Thus, the differential equation \( \frac{dV}{dt} = -kS \) is the differential equation, where \( V \) is the volume, \( S \) is the surface area, and \( t \) is the time in hours.
Based upon the above information, answer the following questions:
(i) Write the order and degree of the given differential equation.}
(ii) Substituting \( V = \pi r^3 \) and \( S = 2 \pi r^2 \), we get the differential equation \( \frac{dr}{dt} = \frac{2}{3}k \). Solve it, given that \( r(0) = 5 \) mm.}
(iii) (a) If it is given that \( r = 3 \) mm when \( t = 1 \) hour, find the value of \( k \). Hence, find \( t \) for \( r = 0 \) mm.}
(iii) (b) If it is given that \( r = 1 \) mm when \( t = 1 \) hour, find the value of \( k \). Hence, find \( t \) for \( r = 0 \) mm.
Time (Hours) | [A] (M) |
---|---|
0 | 0.40 |
1 | 0.20 |
2 | 0.10 |
3 | 0.05 |