Question:

Figure shows variation of Coulomb force (F) acting between two point charges with \( \frac{1}{r^2} \), \( r \) being the separation between the two charges \( (q_1, q_2) \) and \( (q_2, q_3) \). If \( q_2 \) is positive and least in magnitude, then the magnitudes of \( q_1, q_2 \), and \( q_3 \) are such that:
variation of Coulomb force

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Remember that the Coulomb force is proportional to the product of the charges and inversely proportional to the square of the distance between them. If one charge is smaller, it produces less force.
  • \( q_2<q_3<q_1 \)
  • \( q_3<q_1<q_2 \)
  • \( q_1<q_2<q_3 \)
  • \( q_2<q_1<q_3 \)
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The Correct Option is D

Solution and Explanation

To solve the problem, we need to understand the behavior of the Coulomb force between point charges as described by Coulomb's Law:

\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]

where \( F \) is the force between the charges, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the point charges, and \( r \) is the distance between them.

The problem states that \( q_2 \) is positive and is the least in magnitude. We need to determine the relationship between \( q_1 \), \( q_2 \), and \( q_3 \).

Given the force variation with \( \frac{1}{r^2} \), it implies a linear relationship if plotted with the variables appropriately transformed, ensuring that the product of the charges influences the slope. Since \( q_2 \) is the least and positive, any comparison would show that:

  • Given \( q_2 \lt q_1 \lt q_3 \), the influence of \( q_2 \) being the smallest would be appropriate as the force diminishes more quickly with less product magnitude when compared with \( q_1 \) and \( q_3 \).

This establishes that among the choices provided:

\[ q_2 \lt q_1 \lt q_3 \]
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