We are given the expression:
\[
(1 + 5\sqrt{2}x)^9 + (1 - 5\sqrt{2}x)^9
\]
To find the number of terms in the expansion, we use the binomial theorem. The binomial expansion of \( (1 + 5\sqrt{2}x)^9 \) and \( (1 - 5\sqrt{2}x)^9 \) will contain terms of the form:
\[
\binom{9}{k} (5\sqrt{2}x)^k
\]
Expanding each expression:
\[
(1 + 5\sqrt{2}x)^9 = \sum_{k=0}^{9} \binom{9}{k} (5\sqrt{2}x)^k
\]
\[
(1 - 5\sqrt{2}x)^9 = \sum_{k=0}^{9} \binom{9}{k} (-5\sqrt{2}x)^k
\]
When adding the two expansions, terms where \( k \) is odd will cancel out, because the powers of \( x \) will have opposite signs (due to the \( -5\sqrt{2}x \) term), and terms where \( k \) is even will add up.
Thus, only the even terms in both expansions will remain. The even values of \( k \) are \( k = 0, 2, 4, 6, 8 \), so there are 5 terms in the expansion.
Thus, the correct number of terms is 5.
The correct answer is Option A.