1. The given arithmetic progression (A.P.) is:
34, 32, 30, . . .
2. The formula for the sum of the first \(n\) terms of an A.P. is:
\( S_n = \frac{n}{2} \cdot (2a_1 + (n-1) \cdot d) \)
Where \( a_1 \) is the first term, \( d \) is the common difference, and \( n \) is the number of terms.
3. Finding the common difference:
The common difference \( d \) is the difference between any two consecutive terms:
\( d = 32 - 34 = -2 \)
4. Finding the sum of the first 10 terms:
Substitute \( a_1 = 34 \), \( d = -2 \), and \( n = 10 \) into the sum formula:
\( S_{10} = \frac{10}{2} \cdot (2 \cdot 34 + (10-1) \cdot (-2)) \)
\( S_{10} = 5 \cdot (68 + 9 \cdot (-2)) \)
\( S_{10} = 5 \cdot (68 - 18) \)
\( S_{10} = 5 \cdot 50 \)
\( S_{10} = 250 \)