Question:
The number of air molecules per cm3 increased from 3 × 1019 to 12 × 1019. The ratio of collision frequency of air molecules before and after the increase in the number respectively is :
The number of air molecules per cm3 increased from 3 × 1019 to 12 × 1019. The ratio of collision frequency of air molecules before and after the increase in the number respectively is :
Updated On: May 20, 2024
- 0.25
- 0.75
- 1.25
- 0.50
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The Correct Option is A
Solution and Explanation
Collision frequency is given by 𝑍 = 𝑛𝜋𝑑 2𝑉𝑎𝑣𝑔, where n is number of molecules per unit volume.
𝑍1/ 𝑍2 = 𝑛1 /𝑛2 = 3/ 12 = 1/ 4 = 0.25
𝑍1/ 𝑍2 = 𝑛1 /𝑛2 = 3/ 12 = 1/ 4 = 0.25
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