Let's determine the geometry of each molecule:
1. $ BrF_5 $: Bromine has 7 valence electrons. In $ BrF_5 $, there are 5 bond pairs and 1 lone pair. This gives a steric number of 6, which corresponds to an octahedral electron geometry. With 5 bonding pairs and 1 lone pair, the molecular geometry is square pyramidal.
2. $ XeOF_4 $: Xenon has 8 valence electrons. In $ XeOF_4 $, there is one double bond to oxygen and four single bonds to fluorine. There is also one lone pair. This results in a steric number of 6, corresponding to octahedral electron geometry. With 5 bonding pairs and 1 lone pair, the molecular geometry is also square pyramidal.
3. $ SbF_5 $: Antimony has 5 valence electrons. In $ SbF_5 $, there are 5 bond pairs and no lone pairs. The steric number is 5, which corresponds to a trigonal bipyramidal electron and molecular geometry.
4. $ PCl_5 $: Phosphorus has 5 valence electrons. In $ PCl_5 $, there are 5 bond pairs and no lone pairs. The steric number is 5, which corresponds to a trigonal bipyramidal electron and molecular geometry.
Conclusion: Among the given molecules, only $ BrF_5 $ and $ XeOF_4 $ have square pyramidal geometry.
Final Answer:
The final answer is $ BrF_5\ \&\ XeOF_4 $.
The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: